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8x^2+15x-188=0
a = 8; b = 15; c = -188;
Δ = b2-4ac
Δ = 152-4·8·(-188)
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6241}=79$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-79}{2*8}=\frac{-94}{16} =-5+7/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+79}{2*8}=\frac{64}{16} =4 $
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